We are going to be taught to multiply and divide items of measure.
We do the multiplication and division as we do for decimals.
Product of Items of Size:
We will multiply lengths by a quantity, just like the product of abnormal numbers.
1. Multiply 12 km 56 m by 7.
Answer:
12 km 56 m = 12,056 km
So 12,056 × 7 = 84,392 km
2. 44 dams multiply 28 cm by 12
Answer:
28cm = 0.28m
1 dam = 10 m
28 cm = 0.028 bent
Due to this fact, 44 jumps are 28 cm × 12 = 528,336
3. Multiply 7 km 346 m by 6
Answer:
First we convert km and m to m, then we multiply.
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7 km 346 m = 7000m + 346m = 7346 meters Now we multiply by 6 = 7346 × 6 = 44076 meters |
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To transform 44076 m to km, we separate the final 3 digits from the precise and write it as m.
44076 m = 44 km 76 m
So 7 km 346 m x 6 = 44 km 76 m
4. Multiply 15 m 326 mm by 6
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Step I: 326 × 6 = 1956mm = 1000mm + 956mm = 1m 956mm Step II: Sort 956 beneath millimeters and transfer 1 to metre. 15 × 6 = 90 90+ one = 91 meters Step III: Sort 91 beneath the meter. |
Due to this fact, 15 m 326 mm × 6 = 91 m 956 mm
Product of Mass Items:
1. Multiply 15 g 16 mg by 25
Answer:
16 mg = (frac{16}{1000})g
15 g 16 mg = 15.016 g
Therefore, 15 g 16 mg × 25 = 375.4 g
2. 7 kg 4 hg 6 days Multiply 7 g by 15.
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Step I: Multiply the grams. 7 × 15 = 105 g 105 g = 5 g for 10 days Step II: Write 5 beneath gram and transfer 10 to dag. Step III: Multiply the decagrams. 6×15=90 90+ 10 = 100 days 100 days = 10 hg 0 days Step III: Write 0 beneath Dag and transfer 10 to hectograms. Step IV: Multiply the hectograms 4 × 15 = 60 60+ 10 = 70 hours 70 hg = 7 kg 0 hg Step V: Write 0 beneath the hectogram and transfer 7 to kilograms. Step VI: Multiply the kilogram. 7×15=105 kilos 105 + 7 = 112 kilos |
Product of Capability Items:
We will multiply the capability measurement items l and ml by a quantity similar to abnormal numbers.
1. Multiply 9 dℓ 72 mℓ by 6
Answer:
72 mℓ = (frac{72}{100}) dℓ = 0.72 dℓ
9 dℓ 72 mℓ = 9.72 dℓ
So 9.72 dℓ × 6 = 58.32 dℓ
2. Multiply 72 ℓ 250 mℓ by 6
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Answer: First, convert 72 l 250 ml to ml. 72 l 250 ml = 72 × 1000 ml + 250 ml = 72000ml + 250ml = 72250 ml 72250 × 6 = 433500 mi = 433 l 500 ml |
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So 72 l 250 ml × 6 = 433 l 500 ml
3. Multiply 7 l 9 cl 2 ml by 16
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Step I: Write the items so as. Step II: Since deciliter is lacking within the query, write 0 as an alternative. Step III: Multiply the milliliter 2 × 16 = 32 ml 3cl + 2ml Convey the three to centiliters and write 2 beneath the milliliter. Step IV: Multiply the centiliter. 9 × 16 = 144 cl + 3 = 147 cl = 14 dl + 7 cl Step V: Write 7 beneath centiliter and get 14 per deciliter Step VI: multiply deciliter 0 × 16 = 0 0 + 14 = 14 dl = 1 l 4 dl Step VII: Write 4 beneath deciliter and take 1 per liter. Step VIII: multiply by liters 7 × 16 = 112 l 112 + 1 = 113 l Step IX: Write 113 beneath the liter Due to this fact, 7 l 9 cl 2 ml × 16 = 113 l 4 dl 7 cl 2 ml = 113 l 472 ml |
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Division of Size Items:
We will divide lengths by a quantity similar to abnormal numbers are divided. If the measure is given as a mixture of two items similar to km and m or m and cm, we first convert the upper unit to the decrease unit after which divide.
Divide 1.2 km 560 m by 8.
Answer:
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Let’s convert 2 km 560 m to m. 2 km 560 m = 2000m + 560m = 2560 meters Now divide 2560 by 8 |
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So 2 km 560 m ÷ 8 = 320 m
Division of Mass Items:
one. Divide 16 kg 542 g by 6
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Technique One |
Second Technique |
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16 kg 542 g = 16,542 kg  |
16 kg 542 g ÷ 6 = 2 kg 757 g
= 2,757 kilos
Division of Capability Items:
We will divide the capability measurement items l and ml right into a quantity like abnormal numbers.
1. Divide 132 ℓ 64 dℓ by 8
Answer:
64 dℓ = 6.4 ℓ
132 ℓ 64 dℓ = 138.4 ℓ
Therefore, 138.4 ℓ ÷ 8 = 17.3 ℓ
2. Divide 60 l 750 ml by 5
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Answer: When measurements are given as a mixture of two items, we first convert the bigger unit to the smaller unit after which divide. 60 l 750 ml = 60 l + 750 ml = 60000ml + 750ml = 60750 ml Now divide 60750 by 5 60750 ÷ 5 = 12150ml = 12000ml + 150ml = 12 l 150 ml |
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So 60 l 750 ml ÷ 5 = 12 l 150 ml
3. Divide 717 l 32 ml by 8
Answer:
717 l 32 ml = 717000 ml + 32 ml
= 717032 ml
Due to this fact, 717 l 32 ml ÷ 8 = 89629 ml
= 89 l 629 ml
Questions and Solutions on Multiplication and Division in Items of Measure:
1. Multiply the next metric lengths.
(i) 7 by 16 m
(ii) 70 dm 4 cm by 24
(iii) 10 to 22 km
(iv) 84 km by 560 m 51
(v) 34 cm by 25
(vi) 48 cm 9 mm by 62
(vii) 26 m 24 cm 30
(viii) 80 m 5 cm 10
Solutions:
one. (i) 112 meters
(ii) 1689 dm 6 cm
(iii) 220 km
(iv) 4312 km 560 m
(v) 850cm
(vi) 3031cm 8mm
(vii) 78 m 720 cm
(viii) 800 m 50 cm
2. Multiply the next:
(i) 8 kg 225 g × 12
(ii) 12 km 450 m × 17
(iii) 7 kl 3 hl 4 branches × 6
(iv) 5 m 4 dm 8 cm 9 mm × 11
(v) 45 m 28 cm × 8
(vi) 115 kg 25 g × 14
Reply:
2. (i) 98.7 kilos
(ii) 211.65 km
(iii) 44.04 kl
(iv) 60,379 m
(v) 362.24 meters
(vi) 1610.35 kg
3. Divide the next metric lengths.
(i) 6 to 240 km
(ii) 14 km by 580 m 12
(iii) 18 by 36 m
(iv) 50 cm 7 by 4 mm
(v) 8 by 72 m
(vi) 62 m 8 cm 4 by
Solutions:
3. (i) 40 km
(ii) 1 km 215 m
(iii) 2m
(iv) 7 cm 2 mm
(v) 9m
(vi) 15 m 52 cm
4. Divide the next:
(i) 40 km 320 m ÷ 5
(ii) 85 m 67 cm ÷ 13
(iii) 12 kg 264 g ÷ 12
(iv) 13 l 4 dl 8 cl 2 ml ÷ 9
(v) 116 km 280 m ÷ 12
(vi) 2 kg 800 g ÷ 14
Reply:
4. (i) 8,064 km
(ii) 6.59m
(iii) 1,022 kg
(iv) 1,498 liters
(v) 9.69 km
(vi) 0.2 kg
5. Remedy the given:
(i) 56 km × 32
(ii) 32 km 124 m × 4
(iii) 30 m 75 cm ÷ 15
(iv) 47 cm 6 mm ÷ 20
(v) 66 dm 3 cm × 61
Solutions:
5. (i) 1792 km
(ii) 128 km 496 m
(iii) 2 m 5 cm
(iv) 23cm 8mm
(v) 4044 dm 3 cm
6. Multiply the next Metric Capability Measures:
(i) 5 l 750 ml × 4
(ii) 12 l 125 ml × 22
(iii) 13 l 124 ml × 10
(iv) 14 l 120 ml × 7
(v) 44 l 85 ml × 15
(vi) 18 l 33 ml × 51
Solutions:
6. (i) 23 liters
(ii) 266 l 750 ml
(iii) 131 l 240 ml
(iv) 98 l 840 ml
(v) 661 l 275 ml
(vi) 919 l 683 ml
7. Divide the next metric Capability measurements.
Ron, Sam, Mary and Jack got jars of various sizes. They had been all requested to fill a 1 liter can utilizing their jars. Learn how many instances they every have to fill their jars and pour them into their cans.
Solutions:
7. (i) 2 instances
(ii) 5 instances
(iii) 10 instances
(iv) 20 instances
fifth Grade Numbers
fifth Grade Math Issues
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